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a fost răspuns

Aratati ca (x^2+4x+3)(x-1)=(x+1)(x^2+2x-3), pt orice x∈R

Răspuns :

⇒x³-x²+4x²-4x+3x-3=x³+2x²-3x+x²+2x-3
x³+3x²-x-3=x³+3x²+x-3
x³-x³+3x²-3x²-x-x=-3+3
-2x=0
x=0