Răspuns:
Explicație pas cu pas:
E(x)=x²/(x²+1) si F(x)=1/(x²+1) x∈R
a) F(-2)=1/(4+1)=1/5
E(-1/2)=1/4·1/(1/4+1)=1/4·4/5=1/5 ⇒E(-1/2)=F(-2)
b)F(a)=1/(a²+1)
E(1/a)=1/a²/1/(1/a²+1)=(a²+1) ⇒ E(1/a)=F(1/a) ∀a∈R*
c)E(x)+F(x)=x²/(x²+1)+1/(x²+1)=(x²+1)/(x²+1)=1 =constanta ∀x∈R
e) E(x)-F(x)=0
x²/(x²+1)-1/(x²+1)=(x²-1)/(x²+1)=0 ⇒x²-1=0
⇒x∈{-1.1}
d) nu mi-a iesit...
