Răspuns:
Explicație:
10 g CaCl2
masa de CaO
masa de HCl
xg yg 10g
CaO + 2HCl = CaCl2 + H2O
56g 2.36,5g 111g
x =56 .10 : 111 =5,045g CaO
n= 5,045g : 56g/moli=0,09 moli CaO
y= 10 . 73 : 111=6,57 g HCl
n= 6,57 g : 73g/moli= 0,09 moli HCl
MCAO= 40 + 16=56------> 56g/moli
MHCl= 1 + 35,5= 36,5------> 36,5g/moli
MCaCl2= 40 + 2.35,5= 111------> 111g/moli