Răspuns:
Explicație pas cu pas:
[tex]\bf \dfrac{^{3)}1~}{2}+\dfrac{^{2)}1~}{3} =\dfrac{3+2}{6} =\red{\dfrac{5}{6}\rightarrow al ~treilea~numar }[/tex]
[tex]\bf \dfrac{^{2)}1~}{3}+\dfrac{5}{6} =\dfrac{2+5}{6} =\blue{\dfrac{7}{6}\rightarrow al ~patrulea~numar }[/tex]
[tex]\bf \dfrac{5}{6}+\dfrac{7}{6} =\dfrac{5+7}{6} =\dfrac{12^{(6}}{6} =\purple{2\rightarrow al ~cincilea~numar }[/tex]
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[tex]\bf \dfrac{1}{6}+\dfrac{^{2)}2~}{3} =\dfrac{1+4}{6} =\red{\dfrac{5}{6}}[/tex]
[tex]\bf \dfrac{1}{12}+\dfrac{^{2)}5~}{6} =\dfrac{1+10}{12} =\red{\dfrac{11}{12}}[/tex]
[tex]\bf \dfrac{1}{24}+\dfrac{^{2)}11~}{12} =\dfrac{1+22}{24} =\red{\dfrac{23}{24}}[/tex]
==pav38==
