Răspuns:
MFe=56g/mol
MCl2=2x35,5=71g/mol
MFeCl3=56+3x35,5=106,5g/mol
2x56.........3x71g....2x106,5g
2Fe + 3Cl2 → 2FeCl3
40g...........xg.............yg
x=40x3x71/2x56=calculeaza
y=40x2x106,5/2x56=calculeaza
Explicație:
