Răspuns:
[tex] \frac{x + 3}{4} + \frac{2x + 1}{3} = \frac{x - 3}{6} + \frac{3x + 1}{12} \\ [/tex]
[tex] \frac{3x + 9}{12} + \frac{8x + 4}{12} = \frac{2x - 6}{12} + \frac{3x + 1}{12} [/tex]
3x+9+8x+4=2x-6+3x+1
11×+13=5x-5
11×-5×=(-5)-13
6×=-18 =>x= -3
