Răspuns :
[tex]\it x+\dfrac{x}{2}+\dfrac{x}{3}=77|_{\cdot6} \Rightarrow 6x+3x+2x=6\cdot77 \Rightarrow 11x=6\cdot77|_{:11} \Rightarrow x=6\cdot7=42[/tex]
[tex]\it x+\dfrac{x}{2}+\dfrac{x}{3}=77|_{\cdot6} \Rightarrow 6x+3x+2x=6\cdot77 \Rightarrow 11x=6\cdot77|_{:11} \Rightarrow x=6\cdot7=42[/tex]