Răspuns:
a-b=7-8=> a-b=-1
=>a=-1+b <=> a=b-1
=> [3(b-1)+4b][5b-4(b-1)] = (3b-3+4b)(5b-4b+4)
=>(7b-3)(b+4)=0
cazul 1: 7b-3=0
=>7b=3 =>b=3/4
cazul 2: b+4=0
=> b=-4
a=?, b=3/4
a=b-1=3/4-1=-1/4
a=?, b=-4
a=b-1=>-4-1=-5
Solutii:
a1=-1/4
b1=3/4
a2=-5
b2=-4
