Răspuns :
(x-1)³-(x-1)=x(x-1)(x-2)
(x-1)[(x-1)²-1]=x(x-1)(x-2)
(x-1-1)(x-1+1)=x(x-2)
(x-2)x=x(x-2) (A)
(x-1)[(x-1)²-1]=x(x-1)(x-2)
(x-1-1)(x-1+1)=x(x-2)
(x-2)x=x(x-2) (A)
x³-3x²+3x-1 - x+1 = (x-x²)(2-x)
x³ - 3x² + 2x = 2x - 2x² - x² + x³
x³-3x²+2x = x³-3x²+2x (A)
x³ - 3x² + 2x = 2x - 2x² - x² + x³
x³-3x²+2x = x³-3x²+2x (A)