[tex]\bf S\breve a\ se\ verifice\ dac\breve a\ valorile\ indicate\ sunt\ solu\c{\bf t}ii \ pentru\ ecua\c{\bf t}iile:[/tex]
[tex]\it a)\ x=\sqrt3 \Rightarrow \sqrt3+23=4(\sqrt3+5)-3\sqrt3+\sqrt3\cdot\sqrt3 \Rightarrow \\ \\ \Rightarrow 23+\sqrt3=4\sqrt3+20-3\sqrt3+323+\sqrt3=23+\sqrt3\ (A) \Rightarrow x=\sqrt3\ e\ solu\c{\it t}ie[/tex]
[tex]\it b)\ x=0,5 \Rightarrow \dfrac{2\cdot0,2+1}{2}=2\cdot0,5 \Rightarrow \dfrac{1+1}{2}=1 \Rightarrow \dfrac{2}{2}=1 \Rightarrow 1=1\ \ (A) \Rightarrow \\ \\ \Rightarrow x=0,5\ este\ solu\c{\it t}ie[/tex]
[tex]\it c)\ 1,(3)=1\dfrac{3}{9}=\dfrac{\ 12^{(3}}{9} =\dfrac{4}{3}\\ \\ \\ x=\dfrac{4}{3}\Rightarrow 4\cdot\dfrac{4}{3}+5=\dfrac{4}{3} \Rightarrow \dfrac{16}{3}+5-\dfrac{4}{3}=0 \Rightarrow \dfrac{12}{3}+5=0 \Rightarrow 4+5=0 \Rightarrow \\ \\ \Rightarrow 9=0\ \ (F) \Rightarrow x=1,(3)\ nu \ este\ solu\c{\it t}ie[/tex]
