(x-1) / (2/2 +1/2) = (7/3-3/3) / (6/2-3/2)
(x-1) / 3/2 = 4/3 / 3/2
x-1 = 4/3
x= 4/3 +1
x= 4/3 +3/3
x=7/3
[tex]\it \dfrac{x-1}{1+\dfrac{1}{2}}=\dfrac{\dfrac{7}{3}-1}{3-\dfrac{3}{2}} \Rightarrow \dfrac{x-1}{\dfrac{3}{2}}=\dfrac{\dfrac{7}{3}-1}{\dfrac{3}{2}} \Rightarrow x-1=\dfrac{7}{3}-1 \Rightarrow x=\dfrac{7}{3}[/tex]
