Răspuns :
[tex]\it 1,2\cdot(-\dfrac{100}{13})+1,2\cdot\dfrac{30}{13}=\dfrac{1,2}{13}(-100+30)=\dfrac{12}{130}\cdot70=\dfrac{12}{13}\cdot7=\dfrac{84}{13}=6\dfrac{6}{13}[/tex]
[tex]\it 1,2\cdot(-\dfrac{100}{13})+1,2\cdot\dfrac{30}{13}=\dfrac{1,2}{13}(-100+30)=\dfrac{12}{130}\cdot70=\dfrac{12}{13}\cdot7=\dfrac{84}{13}=6\dfrac{6}{13}[/tex]