Răspuns:
Explicație pas cu pas:
a) a²+2ab+b²+5a+5b = (a+b)²+5·(a+b) = (a+b)·(a+b+5)
b) x²-2x+1+a(x-1) = (x-1)²+a·(x-1) = (x-1)·(x-1+a)
c) 4a²+4a+1+2ax+x = (2a+1)²+x(2a+1) = (2a+1)·(2a+1+x)
e) (x+y)²+x²-y² = (x+y)²+(x+y)(x-y) = (x+y)(x+y+x-y) = (x+y)·2x
f) (2a-b)²-4a²+b² = (2a-b)²-(2a-b)(2a+b) = (2a-b)(2a-b-2a-b) =
= (2a-b)·(-2b)
