Răspuns :
Răspuns:
<A+<B+<C=180°
a) A+A+2×A=180
4A=180
A=45°
B=A=45°
C=2×A=2×45=90°
b)A=2×B ,C=3×B+12°
A+B+C=180°
2B+B+3B+12=180°
6B=180-12
6B=168
B=168/6
B=28°
A=2×28
A=56°
C=3×28+12
C=96°
c)A=3×C=>A/3=C ,B=A+12
A+B+C=180°
A+A+12+A/3=180
2A+A/3=180-12
2A+A/3=168
7A/3=168
7A=158×3
7A=504
A=72°
B=72+12
B=84°
72/3=C
C=24°
am notat A unghiul A ,B ungiul B si C unghiul C
[tex]\it a)\\ \\ \hat B=\hat A\ \ \ \ \ \ (1)\\ \\ \hat C=2\hat A\ \ \ \ (2)\\ \\ \hat A+\hat B+\hat C=180^o\ \stackrel{(1),(2)}{\Longrightarrow}\ \hat A+\hat A+2\hat A=180^o \Rightarrow \\ \\ \Rightarrow4\hat A=180^o|_{:4} \Rightarrow \hat A=45^o\ \ \ \ \ (3)[/tex]
[tex]\it (1),\ (3) \Rightarrow \hat B=45^o\\ \\ (2),\ (3) \Rightarrow \hat C=2\cdot45^o=90^o[/tex]
[tex]\it b)\\ \\ \hat A=2\hat B\ \ \ \ \ \ (1)\\ \\ \hat C=3\hat B+12^o\ \ \ \ (2)\\ \\ \hat A+\hat B+\hat C=180^o\ \stackrel{(1),(2)}{\Longrightarrow}\ 2\hat B+\hat B+3\hat B+12^o=180^o|_{-12^o} \Rightarrow \\ \\ \Rightarrow 6\hat B=168^o|_{:6} \Rightarrow \hat B=28^o\ \ \ \ \ (3)[/tex]
[tex]\it (1),\ (3) \Rightarrow \hat A=2\cdot28^o=56^o\\ \\ (2),\ (3) \Rightarrow \hat C=3\cdot28^o+12^o =96^o[/tex]
[tex]\it c)\\ \\ \hat A=3\hat C\ \ \ \ \ \ (1)\\ \\ \hat B=\hat A+12^o=3\hat C+12^o\ \ \ \ (2)\\ \\ \hat A+\hat B+\hat C=180^o\ \stackrel{(1),(2)}{\Longrightarrow}\ 3\hat C+3\hat C+12^o+\hat C=180^o|_{-12^o} \Rightarrow \\ \\ \Rightarrow 7\hat C=168^o|_{:7} \Rightarrow \hat C=24^o\ \ \ \ \ (3)[/tex]
[tex]\it (1),\ (3) \Rightarrow \hat A=3\cdot24^o=72^o\\ \\ (2),\ (3) \Rightarrow \hat B=3\cdot24^o+12^o =84^o[/tex]