[tex]\it i)\ =-\dfrac{9}{16}\cdot\dfrac{8}{27}+1=-\dfrac{1}{6}+1=\dfrac{5}{6}\\ \\ \\ j)\ = -1\cdot(-\dfrac{125}{64})+(-\dfrac{5}{64})=\dfrac{125}{64}-\dfrac{5}{64}=\dfrac{120^{(8}}{64}=\dfrac{15}{8}\\ \\ \\ k)\ =\Big(1-\dfrac{11}{6}\cdot\dfrac{6}{11}\Big)^{2020}\cdot\dfrac{3}{5}-\dfrac{9}{49}=0\cdot\dfrac{3}{5}-\dfrac{9}{49}=-\dfrac{9}{49}[/tex]
