Răspuns: [tex]\purple{\underline{\bf M_{g}=2}}[/tex]
Explicație pas cu pas:
[tex]\bf a = 4-2\sqrt{3}[/tex]
[tex]\bf b = 4+\sqrt{12} =4+\sqrt{2^{2}\cdot 3} \implies b = 4+2\sqrt{3}[/tex]
[tex]\bf \red{Media_{~geometrica}=\sqrt{a\cdot b} }[/tex]
[tex]\bf M_{g}=\sqrt{(4-2\sqrt{3})\cdot (4+2\sqrt{3})}[/tex]
[tex]\bf M_{g}=\sqrt{(4^2-(2\sqrt{3})^2}=\sqrt{16-2^2\cdot 3}[/tex]
[tex]\bf M_{g}=\sqrt{16-4\cdot 3}=\sqrt{16-12} =\sqrt{4}[/tex]
[tex]\purple{\underline{\bf M_{g}=2}}[/tex]
