Răspuns:
[tex]4 \sqrt{3} - 7 < 0 \\ 3 \sqrt{7} - 8 < 0 \\ (7 - 4 \sqrt{3} )(8 + 3 \sqrt{7}) = 56 + 21 \sqrt{7 } - 12 \sqrt{21} [/tex]
[tex]4 \sqrt{3} - 7 < 0 \\ 3 \sqrt{7} - 8 < 0 \\ (7 - 4 \sqrt{3} )(8 + 3 \sqrt{7}) = \\ 56 + 21 \sqrt{7 } - 12 \sqrt{21} \\ (8 - 3\sqrt{7} )(7 + 4 \sqrt{3} ) = \\ 56 + 24 \sqrt{3} - 12 \sqrt{21 } [/tex]
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