Va rog este tare urgent! Descompuneti in factori expresiile urmatore utilizand, eventual, identitatile. Nu raspundeti aiurea!!
![Va Rog Este Tare Urgent Descompuneti In Factori Expresiile Urmatore Utilizand Eventual Identitatile Nu Raspundeti Aiurea class=](https://ro-static.z-dn.net/files/dc5/770c84d6773e95b282f8f9d54df2e954.png)
Răspuns:
a) [tex]x^{2} + 6x+8= (x+2) (x+ 4)=[/tex][tex]x^{2}[/tex] +2x+4x+8 = [tex]x^{2}[/tex]+ (2+4)x +2*4
b) [tex]x^{2} -10x+9[/tex]= (x- 9)(x-1) = [tex]x^{2} -(9+1)x + 9*1[/tex]
c) [tex]x^{2}[/tex] -20x+96= (x- 8) (x-12)= [tex]x^{2}[/tex] - (8+12)[tex]x[/tex] + 8*12
d) [tex]x^{2}[/tex]- 8x- 9=(x +1) (x-9)= [tex]x^{2}[/tex] - (1-9)[tex]x[/tex] -9*1
e) [tex]x^{2}[/tex]- 14x+ 24= (x-2 )(x- 12)= [tex]x^{2} -[/tex](2+12)[tex]x[/tex] +2*12
f) [tex]x^{2}[/tex]- 7x + 10= (x-2) (x-5)= [tex]x^{2} - (2+5)x + 2*5[/tex]
g) [tex]x^{2}[/tex]- 15x+ 56= (x-7)(x-8)= [tex]x^{2} - (7+8)x +7*8[/tex]
h) [tex]x^{2}[/tex]+ 23x + 60= (x+ 20)(x+3)= [tex]x^{2} +(20+3)x +20*3[/tex]
i) [tex]x^{2}[/tex]+ 17x - 60=(x-3) (x+20) = [tex]x^{2} + (20-3) x - 3*20[/tex]