Răspuns :
36/(x+3) ∈ N unde x+3 ∈D36
D36={1,2,3,4,6,9,12,18,36}
Fie x+3 = 1 ⇒ x = -2 ∉ N
x+3 = 2 ⇒ x = -1 ∉ N
x+3 = 3 ⇒ x = 0 ∈ N
x+3 = 4 =⇒ x = 1
x+3 = 6 ⇒ x = 3
x+3 = 9 ⇒ x = 6
x+3 = 12 ⇒ x = 9
x+3 = 18 ⇒ x = 15
x+3 =36 ⇒ x = 33
A={0,1,3,6,9,15,33}
Răspuns:
Explicație pas cu pas:
D₃₆={ 1,2,3,4,6,9,12 , 18 ,36 }.............D₃₆= divizorii lui 36
-
x+3=1
x=1-3
x=-2 ∉ N
-
x+3=2
x= 2-3
x= 1∉N
-
x+3= 3
x= 3-3
x=0∈ N
-
x+3= 4
x=4-3
x=1 ∈N
-
x+3=6
x= 6-3
x=3∈N
-
x+3=9
x= 9-3
x=6 ∈N
-
x+3=12
x=12-3
x= 9∈N
-
-
x+3=18
x= 18-3
x=15∈N
-
x+3= 36
x= 36-3
x=33 ∈ N
x∈{ 0,1,3,6,9 ,15 , 33 }