[tex]\it a=3,75=\dfrac{\ 375^{(25}}{100}=\dfrac{15}{4}\\ \\ \\ b=0,2(7)=\dfrac{27-2}{90}=\dfrac{\ 25^{(5}}{90}=\dfrac{5}{18}\\ \\ \\ m_g=\sqrt{ab}=\sqrt{\dfrac{15}{4}\cdot\dfrac{5}{18}}=\sqrt{\dfrac{\ 75^{(3}}{72}}=\sqrt{\dfrac{25}{24}}=\dfrac{^{\sqrt6)}5}{\ 2\sqrt6}=\dfrac{5\sqrt6}{12}[/tex]
