Explicație pas cu pas:
[tex] \dfrac{24}{5 \sqrt{3} } - \dfrac{12}{ \sqrt{9} } + \dfrac{21}{10 \sqrt{6} } - \dfrac{28}{2 \sqrt{6} } = [/tex]
[tex]\dfrac{24 \sqrt{3} }{5 \cdot3 } - \dfrac{12}{ 3 } + \dfrac{21 \sqrt{6} }{10 \cdot6} - \dfrac{28 \sqrt{6} }{2 \cdot6} = [/tex]
[tex]\dfrac{ ^{12)}8 \sqrt{3} \: }{5 } - \dfrac{^{60)}4 \: }{ 1 } + \dfrac{^{3)}7 \sqrt{6} }{20} - \dfrac{^{20)}7\sqrt{6} \: }{3} =[/tex]
[tex]\dfrac{ 96\sqrt{3} }{60}- \dfrac{240 }{60 }+ \dfrac{21 \sqrt{6} }{60} - \dfrac{140\sqrt{6}}{60} =[/tex]
[tex]\dfrac{ 96 \sqrt{3} - 240 + 21 \sqrt{6} - 140\sqrt{6}}{60} = [/tex]
[tex]\red{\boxed{\dfrac{ 96\sqrt{3} - 240 - 119\sqrt{6}}{60}}}[/tex]