[tex]\it \dfrac{x}{y}= \dfrac{10}{2} \Rightarrow \dfrac{x}{y}=5 \Rightarrow \dfrac{x}{y}=5 \Rightarrow x=5y\ \ \ \ \ (*)\\ \\ \\ \dfrac{6x-2y}{7x-3y}\ \stackrel{(*)}{=}\ \dfrac{6\cdot5y-2y}{7\cdot5y-3y}= \dfrac{28y}{32y}= \dfrac{\ 28^{(4}}{32}= \dfrac{7}{8}[/tex]
