Răspuns :
36-16=20 (suma laturilor congr)
20:2=10 cm (au lat congr.)
Daca ABC este triunghiul AB=AC duce inalt AD si in tr ABD aplic Pitagora AD=6(6,8,10 sun nr pitagorice)
Atr=BC.AD/2=16.6/2=48 cm^2
20:2=10 cm (au lat congr.)
Daca ABC este triunghiul AB=AC duce inalt AD si in tr ABD aplic Pitagora AD=6(6,8,10 sun nr pitagorice)
Atr=BC.AD/2=16.6/2=48 cm^2
Fie triunghiul ABC
Pabc = AB + AC + BC = 36cm
AB = AC
BC = 16cm
AB + AC = 36cm - 16cm
AB + AC = 20cm
20cm : 2 = 10cm
AB = AC = 10cm
Se duce AD inaltime pe baza BC
Se aplica Pitagora,
AD = 6 (6, 8, 10 sunt numere pitagorice)
[tex]Aria = \frac{b*h}{2} = \frac{16*6}{2} [/tex]
[tex] \frac{16*6}{2} = 8 * 2 = 16 cm^{2} [/tex]
Pabc = AB + AC + BC = 36cm
AB = AC
BC = 16cm
AB + AC = 36cm - 16cm
AB + AC = 20cm
20cm : 2 = 10cm
AB = AC = 10cm
Se duce AD inaltime pe baza BC
Se aplica Pitagora,
AD = 6 (6, 8, 10 sunt numere pitagorice)
[tex]Aria = \frac{b*h}{2} = \frac{16*6}{2} [/tex]
[tex] \frac{16*6}{2} = 8 * 2 = 16 cm^{2} [/tex]