Răspuns :
[tex]\it =\Big(\dfrac{7}{3}+\dfrac{2}{3}\Big)\cdot\Big(\dfrac{^{5)}1}{\ 4}+\dfrac{^{2)}6}{\ \ 10}\Big)=3\cdot\dfrac{17}{20}=\dfrac{^{5)}51}{\ 20}=\dfrac{255}{100}=2,55[/tex]
[tex]\it =\Big(\dfrac{7}{3}+\dfrac{2}{3}\Big)\cdot\Big(\dfrac{^{5)}1}{\ 4}+\dfrac{^{2)}6}{\ \ 10}\Big)=3\cdot\dfrac{17}{20}=\dfrac{^{5)}51}{\ 20}=\dfrac{255}{100}=2,55[/tex]