Răspuns:
-6
Explicație pas cu pas:
b=[tex]8\sqrt{6} :2\sqrt{3} -2(1+\sqrt{8})[/tex]
b=[tex]\frac{8\sqrt{6} }{2\sqrt{3}}-2-2\sqrt{8}[/tex] atribuim la termenii liberi [tex]2\sqrt{3}[/tex]
b=[tex]\frac{8\sqrt{6} -4\sqrt{3} -4\sqrt{24}}{2\sqrt{3} }= \frac{2\sqrt{3} (4\sqrt{2} -2-2\sqrt{8} ) }{2\sqrt{3} }[/tex]simplificam expresia
b=[tex]4\sqrt{2} -2-2\sqrt{2^2*2} =4\sqrt{2} -2-4\sqrt{2} =-2[/tex]
b=-2
Avem 1+b-1+b-2=1+(-2)-1+(-2)-2=1-2-1-2-2=-6
