Răspuns:
[tex]sinB=\frac{3\sqrt{2}}{2}[/tex]
Explicație pas cu pas:
Conform teoremei sinusului:
[tex]\frac{AB}{sinC} = \frac{AC}{sinB} \\\\\frac{\frac{4}{2}}{sin45а} = \frac{6}{sinB} \\\\\frac{2}{\frac{\sqrt{2}}{2} } = \frac{6}{sinB} \\\\\frac{4}{\sqrt{2}} = \frac{6}{sinB} \\\\sinB = \frac{6\sqrt{2}}{4}\\\\sinB=\frac{3\sqrt{2}}{2}[/tex]
