[tex]\it \Big(\dfrac{2}{3\sqrt3+5}+\dfrac{1}{5+2\sqrt6}\Big)\cdot\dfrac{\sqrt3}{3-2\sqrt2}=\Big(\dfrac{2(3\sqrt3-5)}{(3\sqrt3)^2-5^2}+\dfrac{5-2\sqrt6}{5^2-(2\sqrt6)^2}\Big)\cdot\\ \\ \\ \cdot \dfrac{\sqrt3}{3-2\sqrt2}=\Big(\dfrac{2(3\sqrt3-5)}{(3\sqrt3)^2-5^2}+\dfrac{5-2\sqrt6}{5^2-(2\sqrt6)^2}\Big) \cdot \dfrac{\sqrt3}{3-2\sqrt2}=[/tex]
