Răspuns:
1) 11g H.........................33gCO2
44g...............................X
X=44x33/11=132gCO2 ; M CO2=44 ;
132/44=3moli =>C3 C3H8
2)C3H8 +Cl2=C3H7Cl +HCl
M C3H8=44 ; 1760/44=40kmoli
1mol C3H8....................1molCl2
X....................................32
X=32 kmoli reactioneaza
40-32=8 kmoli neract
din raportul 1/x/1 =>nr moli nereact=nr moli 1-clor propan=8
x=32-8=24 kmoli 2-clorpropan
3) formula unei H CnH(2n+2)
2n+2=22 =>n=10 C10H22
M C4H10 =58
435/58=7,5moli
7,5moli.............................6moli izobutan
100.....................................X
X=600/7,5=80
Explicație: