Explicație pas cu pas:
[tex] \bf\dfrac{x}{y} = \dfrac{7}{2} \implies 7y = 2x \implies y = \dfrac{2x}{7}[/tex]
[tex] \bf \dfrac{3x+5y}{2x+y}=\dfrac{3x + 5 \cdot\dfrac{2x}{7}}{2x + \dfrac{2x}{7} } = \dfrac{3x + \dfrac{10x}{7}}{\dfrac{14x + 2x}{7} } = [/tex]
[tex] \bf \dfrac{\dfrac{21x + 10x}{7}}{\dfrac{16x}{7} } = \dfrac{\dfrac{31x}{7}}{\dfrac{16x}{7} } = \dfrac{31x}{7} : \dfrac{16x}{7} = [/tex]
[tex]\bf \dfrac{31 \not x}{ \not7} \cdot \dfrac{ \not7}{16 \not x} = \red{ \boxed{ \bf \: \dfrac{31}{16} \: }}[/tex]
