ducem DM_I_AB
AM=(AB-DC)/2=(24-16)/2=4
h=DM=√(8²-4²)=√(64-16)=√48=4√3
A=(24+16)×4√3/2=80√3
B=24
b=16
BC=8
h=4√3
Notam O raza cercului cimcumscris care se gaseste la intersectia mediatoarelor laturilor CD si BC
ducem OE_I_CD
ducem OF_I_BC
intersectia lui OE cu AB=(G)
notam OG=x
ED=16/2=8
GB=24/2=12
in ΔOED ⇒ OD²=ED²+OE²=8²+(4√3+x)² =64+48+8x√3+x²=112+8x√3+x²
in ΔOGB ⇒ OB²=GB²+OG²=12²+x² =144+x²
144+x²=112+8x√3+x²
144=112+8x√3
32=8x√3
x=32/8√3=4/√3=4√3/3
R=OE=4√3+4√3/3 =(12√3+4√3)/3=16√3/3
