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Popmaria447
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(/5x-1)¬2=(/5x-7)(7+/5x)
/----ii  radical
¬2---------totul la  a  2

Răspuns :

Ctinamaria31xxx
(/5x-1)¬2=(/5x-7)(7+/5x)

(r5x-1)^2=(r5x)^2-2xr5+1=
5x^2-2xr5+1

(/5x-7)(7+/5x)

(r5x-7)(r5+7)=5x^2-49

5x^2-2xr5+1=5x^2-49
2xr5=-49-1
2xr5=-50
xr5=-25
x=-25/r5
x=-25r5/5
x=-5r5

^=putere
r=radical

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