a)
ms= 30 g
c%= 64%
-----------------/---
md= ?g
----------------//---
stim ca c% = mdx100/ms
=> md = msxc%/100 = 30x64/100 = 19,2 g zahar dizolvat
b)
m.apa.evaporata = 120 g
ms1 = 380 g
c1%= 25%
-------------------/------
c.f.% = ?%
-----------------//------
ms2= ms1 - m.apa.evaporata = 380-120 = 260 g
md = ms1xc1/100 = 380x25/100 = 95 g
=> c.f. = mdx100/ms2 = 95x100/260 = 36,54%
dupa evaporarea apei solutia s-a concentrat, deoarece conc. a crescut fata de cea initiala