Răspuns:
[tex]a = \frac{6}{ \sqrt{2} } \\ a = \frac{6 \sqrt{2} }{ \sqrt{2} \times \sqrt{2} } \\ a = \frac{6 \sqrt{2} }{2} = 3 \sqrt{2 } \\ b = \frac{10}{ \sqrt{5} } \\ b = \frac{10 \sqrt{5} }{ \sqrt{5} \times \sqrt{5} } \\ b = \frac{10 \sqrt{5} }{5} = 2 \sqrt{5} \\ a = 3 \sqrt{2} = \sqrt{ {3}^{2} \times 2 } = \sqrt{9 \times 2} = \sqrt{18} \\ b = 2 \sqrt{5} = \sqrt{ {2}^{2} \times5 } = \sqrt{20 } \\ \sqrt{18} < \sqrt{20} \: rezulta \: ca \: a < b[/tex]
