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Talababiancaio
a fost răspuns

Aflați numărul necunoscut (a)
1. 232+[48×25+(540×a-82×5)×10]÷100=797
2. 88-8×(60×88-a)÷33-720÷120+90÷15=8
3. 7+3×[(135×6-945÷a+118×5)÷5+4×(195÷ 15+180 ÷20 -7 )]=964
4. (65+35)÷100-a÷[6-5×(18-4×4)÷2]+0÷3=0
5. 3+3×{3+3×[3+3×(3+a÷3)+3]+3}÷3=63
6. 1+1×{1+1×[1+a×(1+1) +1 ]+1}+1 = 8
7. 110+11÷{10+100÷[10+10×(10-10÷a)]}-100
=11

Răspuns :

Danielar12
1.[48x25+(540xa-82x5)x10]:100=797-232
1200+(540xa-410)x10=565x100
(540xa-410)x10=56500-1200
540xa-410=55300:10
540xa=5530+410
540xa=5940
a=5940:540
a=11
2.88-8x(60x88-a):33-6+6=8
-8x(60x88-a):33=8-88
-8x(60x88-a):33=-80
(60x88-a):33=80:8
60x88-a=10x33
5280-a=330
a=5280-330
a=4950
restul le faci la fel tinand cont de trecerea peste egal cu semn schimbat

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