Amestec echimolar => nr egal de moli => putea lua 1:1
MCu=64g/mol
MCuCO3=64+12+48=124g/mol
deoarece amestecul contine si impuritati vom calcula masa amestecului cu impuritati
mamestec...........100%
128g....................38,4%
mamestec=128*100/38,4=333,33g amestec cu impuritati
64+124=188g amestec pur
puritate=mpura*100/mimpura=188*100/333,333=56,4%
