Răspuns:
a) (x -2) x (x^2+3x-1) - (x^2) x (1-2x) + x(2x + 3) =
= x^3 +3x + x -2x^2 - 6 - 2 - ( x^2 - 2x^3) + 2x^2 + 3x =
= x^3 + x - 6 - 2 - x^2 + 2x^3 =
= 3x^2 - x^2 + x - 8
b) (x² + 1) (3x - 1) - (2x)² (3x - 2) + 7 x (3 x² + 3) =
=3 x³ + 3 x - x² - 1 - 4 x² ( 3 x - 2) + 21 x³ + 21 x =
= 24 x³ + 24 x - x² - 1 - 12 x³ + 8 x² =
= 12 x³ + 7 x² + 24 x - 1
c) (x²+y+1) x (3x-y) - (2x)² x (x-y) +2x ori (3x²-2y)=
(3x³+3xy+3x-x²y-y²-y) - (4x) x ²(x-y)+ 6x³- 4xy=
3x³ - 3xy + 3x - x²y-y²-y - 4x³+4x²y+6x³-4xy=
5x³+3x²y-7xy+3x-y²-y
Explicație pas cu pas:
Spor si success!
Pls coroana!
