Răspuns:
a) [tex]\frac{x+1}{3x+3}=\frac{x+1}{3(x+1)} =\frac{1}{3}[/tex]
b)[tex]\frac{x^{2}+2x+1 }{x^{2} +x} =\frac{(x+1)^{2} }{x(x+1)} =\frac{x+1}{x}[/tex]
c) [tex]\frac{x^{2} -1}{x^{2} +2x+1}=\frac{(x-1)(x+1)}{(x+1)^{2} } =\frac{x-1}{x+1}[/tex]
Explicație pas cu pas:
