Răspuns:
[tex]33 \times {3}^{30} \div + 7 \times {3}^{31} + {3}^{33} = \\ {3}^{30} (33 \times 1 + 7 \times {3}^{1} + {3}^{3} = \\ {3}^{30} (33 + 7 \times 3 + 27) = \\ {3}^{30} (33 + 21 + 27 ) = \\ {3}^{30} \times 81 = \\ {3}^{30} = ({3}^{15})^{2} \\ 81 = {9}^{2} \\ ({3}^{15})^{2} + {9}^{2} = ( { 3}^{15} \times 9)^{2} - patrat perfect[/tex]
Sper ca te am ajutat!
