Răspuns :
[tex]\it Din\ \Delta VAB,\ EM||VA\ \stackrel{T.Thales}{\Longrightarrow}\ \dfrac{BE}{EV}=\dfrac{BM}{MA}\ \ \ \ \ (1)\\ \\ \\ Din\ \Delta ABC,\ MP||AC\ \stackrel{T.Thales}{\Longrightarrow}\ \dfrac{BM}{MA}=\dfrac{BP}{PC}\ \ \ \ \ (2)\\ \\ \\ (1),\ (2) \Rightarrow \dfrac{BE}{EV}=\dfrac{BD}{PC}\ \stackrel{R.T.Thales}{\Longrightarrow}\ \ PE||CV[/tex]