Răspuns:
DATE NECESARE
miu,NaOH= 40g/mol
miu,Cu(OH)2---> 98g/mol
c= mdx100/ms
-calculez masa si moli NaOH
md= cxms/100 = 4x200/100g= 8g
niu=m/miu= 8/40mol= 0,2mol NaOH
-deduc moli si masa Cu(OH)2 din ecuatia chimica
2mol......................................................1mol
2NaOH + CuCl2-----> 2NaCl + Cu(OH02↓
0,2mol......................................................x
x= niu= 0,1mol Cu(OH)2
m=niuxmiu= 0,1x98g= 9,8g precipitat
Explicație:
