Răspuns :
[tex]4(x-1)^{2} -7 \leq (2x+5)^{2}[/tex]
Desfacem parantezele si efectuam calculele.
[tex]4*(x^{2}-2x+1) -7 \leq (4x^{2}+20x+25)[/tex]
[tex]4x^{2}-8x+4-7 \leq 4x^{2}+20x+25[/tex]
[tex]-8x-3 \leq 20x + 25[/tex]
[tex]-28 \leq 28x[/tex]
[tex]-1 \leq x[/tex]
[tex]x \geq -1[/tex]
Desfacem parantezele si efectuam calculele.
[tex]4*(x^{2}-2x+1) -7 \leq (4x^{2}+20x+25)[/tex]
[tex]4x^{2}-8x+4-7 \leq 4x^{2}+20x+25[/tex]
[tex]-8x-3 \leq 20x + 25[/tex]
[tex]-28 \leq 28x[/tex]
[tex]-1 \leq x[/tex]
[tex]x \geq -1[/tex]
4(x-1)² ≤(2x+5)²=
(4x-4)²≤4x²+25
16x²-16≤4x²+25
16x²-4x²≤25+16
12x≤41
x≤41:12
x≤3,416
x∈{3,2,1,0}
(4x-4)²≤4x²+25
16x²-16≤4x²+25
16x²-4x²≤25+16
12x≤41
x≤41:12
x≤3,416
x∈{3,2,1,0}
