Răspuns:
[tex] {10}^{6} {10}^{14} \div {25}^{6} = {10}^{20} \div {25}^{6} = {5}^{20} {2}^{20} \div {5}^{6} {5}^{1} = {5}^{6} ( {5}^{14} {2}^{20} \div 5)b {15}^{40} \div {27}^{6} = {3}^{40} {5}^{40} \div {3}^{18} = {3}^{18} ( {3}^{22} {5}^{40} \div {3}^{0} )[/tex]
