[tex]\left(-\sqrt{3}\right)^{-4}= \dfrac{1}{\left(-\sqrt{3}\right)^4} = \dfrac{1}{\left(-\sqrt{3}\right)^{2\cdot 2}} \dfrac{1}{\left[\left(-\sqrt{3}\right)^2\right]^2} = \dfrac{1}{3^2} = \dfrac{1}{9} = 0,(1)[/tex]
