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Suhatchi98
a fost răspuns

Simplificati fractia algebrica:
X la cub +8 / X la patrat +4X+4

Răspuns :

Vlad2000
(x³ +8) / (x² +4x +4) = (x³ +2³) / (x+2)² = (x+2)(x² -2x +4) / (x+2)²
= (x-2)² / (x+2)

a³ + b³ = (a+b)(a²-ab+b²)
Alesyo
[tex]x^2+8= (x+4)(x-4) x^2+4x+4=0 a=1 b=4 c=4 delta = b^{2}-4ac = 4^2-4*1* 4=16-16=0 x_{1} = \frac{-4+0}{2}=-2 delta= 0 o radacina a(x-x1)(X-x2) (x+2)(x+2)[/tex]
[tex](x+4)(x-4)/(x+2)(x+2) = x-4[/tex]

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