Ma puteți ajuta??????
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Bună!
[tex] \sqrt{48} \div \sqrt{2} + \sqrt{162} \times \sqrt{3} = [/tex]
[tex] = \sqrt{24} + \sqrt{162} \sqrt{3} = [/tex]
[tex] = \sqrt{24} + \sqrt{486} = [/tex]
[tex] = 2 \sqrt{6} + \sqrt{486} = [/tex]
[tex] = 2 \sqrt{6} + 9 \sqrt{6} = [/tex]
[tex] = 11 \sqrt{6} [/tex]