Răspuns:
Explicație pas cu pas:
[tex]2^{15} + 2\cdot4^7} = 2^{15} + 2\cdot(2^2)^7 = 2^{15} + 2\cdot2^{2\cdot7} = 2^{15} + 2\cdot2^{14}= 2^{15} + 2^{14+1}=\\\\= 2^{15}+2^{15} = 2^{15}(1+1)=2^{15}\cdot2 = 2^{15+1}=2^{16}=2^{2\cdot8}=(2^{2})^8=4^8\\\\5^8 > 4^8 = 2^{25} + 2\cdot4^7}[/tex]
[tex]5^{14} = 5^{2\cdot7} = (5^2)^7 = 25^7 < 27^7 = (3^3)^7 = 3^{3\cdot7} = 3^{21}[/tex]
