Notam Alina=A Stefan=S Mama=M Tata=T
[tex]A+S+M+T= 82[/tex]
[tex](M+3)=4*(S+3)[/tex]
[tex](T+3)=6*(A+3)[/tex]
[tex]S=A+2[/tex]
In ecuatia [tex](M+3)=4*(S+3)[/tex] inlocuim stiind faptul ca S=A+2
[tex]M+3=4*(A+5) =\ \textgreater \ M+3=4*A+20 =\ \textgreater \ M= 4*A+17[/tex]
La fel si in [tex](T+3)=6*(A+3)[/tex]
[tex]T+3=6*A+18 =\ \textgreater \ T=6*A + 15[/tex]
Luam apoi fiecare ecuatie si cea cu M=4A+17 si cea cu T=6A+15 dar si S=A+2 si inlocuim in prima:
[tex]A+A+2+4*A+17+6*A+15 = 82 [/tex]
[tex]12*A=48 =\ \textgreater \ A=4 [/tex] Alina are 4 ani.
[tex]S=A+2=4+2=6[/tex] Stefan are 6 ani.
[tex]M=4*A+17=4*4+17=33[/tex] Mama are 33 de ani.
[tex]T=6*A+15=6*4+15=24+15=39[/tex] Tatal are 39 de ani.
