Răspuns:
Bună,
[tex](3 ^{32} \div {3}^{2} + 2 ^{2} \times {2}^{25} - 2019^{0}) \div ( {27}^{10} + {8}^{9} - 324 \div {18}^{2} ) = \\ (3 ^{32 - 2} + {2}^{2 + 25} - 1) \div ((3 ^{3}) ^{10} + ({2}^{3})^{9} - 1) \\ ( {3}^{30} + 2^{27} - 1) \div (3 ^{30 } + 2 ^{27} - 1) = \\ 1 [/tex]
Sper că te-am ajutat.❤️
