[tex]\it a)\ \ (5^4)^6=5^{4\cdot6}=5^{24}\\ \\ b)\ \ (7^8)^3=7^{8\cdot3}=7^{24}\\ \\ c)\ \ (23^1)^{17}=23^{1\cdot17}=23^{17}\\ \\ d)\ \ (13^{11})^7=13^{11\cdot7}=13^{77}\\ \\ e)[(3^2)^3]^4=3^{2\cdot3\cdot4}=3^{24}\\ \\ f)\ \ [(8^5)^3]^6=8^{5\cdot3\cdot6}=5^{90}\\ \\ g)\ \ [(13^5)^6]^4=13^{5\cdot6\cdot4}=13^{120}\\ \\ h)\ \ [(9^2)^7]^{11}=9^{2\cdot7\cdot11}=9^{154}[/tex]
Am utilizat regula:
[tex]\it (a^n)^k=a^{n\cdot k}[/tex]
