[tex]a=(1+\frac{1}{12} ):\frac{26}{3} +|2^{3} - 3^{2} | -\frac{1}{8}[/tex]
[tex]a=\frac{13}{12} * \frac{3}{26} + 3^{2} -2^{3} -\frac{1}{8}[/tex]
[tex]a=\frac{1}{8} +9-8-\frac{1}{8} \\[/tex]
a=1, 1 aparține N => a este natural (a)
[tex]b=(\frac{21}{4} - \frac{8}{3})*\frac{24}{31} + 2021^{0}[/tex]
[tex]b=(\frac{63-32}{12} )*\frac{24}{31} +1[/tex]
[tex]b=\frac{31}{12} * \frac{24}{31} +1\\b=2+1=3\\Ma=\frac{a+b}{2} =\frac{1+3}{2} =\frac{4}{2} =2[/tex] (b)
